Which equations are correct? select each correct answer. −3y5(2y3 3)=−6y8−9y5 −5x3(3x3 2)=−15x9−10x3 −2c6(5c3 6)=−10c9−12c6 −4b4(5b2 6)=−20b8−24b3.

Calculate the ph at the equivalence point for the titration of a solution containing 150.0 mg of ethylamine (c2h5nh2) with 0.1000 m hcl solution. the volume of the solution at the equivalence point is 250.0 ml. kb forethylamine is 4.7 × 10−4 .