A hydrogen atom is in a d state. In the absence of an external magnetic field the states with different ml have (approximately) the same energy. Consider the interaction of the magnetic field with the atom's orbital magnetic dipole moment. Part A Calculate the splitting (in electron volts) of the ml levels when the atom is put in a 0.800 T magnetic field that is in the z-direction.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

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c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.