A 15 g ice sample at -5°C is heated to water at 100°C. Calculate the ampount of heat needed. Specific heat of water and ice are 4.184 J/g °C and 2.108 J/g °C respectively. And heat of fusion is 6.01 kJ/mol

10.063g / 10.00 ml = 1.0063 g/ml which rounds off to 4 sig figs as: 1.006 g/ml

Ithink this is what you meant. the temperature at which a liquid begins to boil is called the boiling point. the boiling point of water is 212°f or 100°c.  and at that point will start to turn into steam (gas)

It is 4.92 e-4 sorry if i am wrong