AH HELP IM TIMEd WILL BRAINLIEST

211.0

Explanation:

∆G(free energy) = ∆H(enthalpy) - T∆S(entropy)

∆H = 215KJ/mol

T = 90°C = 273 + 90

= 363K

∆S = 11J/mol/K or 11 × 10^-3kJ/mol/K

∆G = 215- 363(11 × 10^-3)

= 215 - 3.993

= 211.007

To the nearest tenth 211.0

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g