what is the ph of the analyte in a titration at the equivalence point when a 10.00 ml aliquot of 0.25 m hf ( ka = 3.5 x 10-4, pka = 3.46) is titrated with 0.10 m naoh?

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

The answer is b because a,c,and d are opinons

Answer it is also known as the completion state is untrue of the activation complex;

Hello! data: p (pressure) = 1.25 atmv (volume) = ? (in l)t (temperature) = 298 kn (number of mols) = 0.900 molesr (gas constant) = 0.082 (atm*l/mol*k)apply the data to the clapeyron equation (ideal gas equation), see: i hope this . =)