8. What is the coefficient of ammonia gas after balancing the following equation? N2(9) +
- H2(g) --> --NH3(9)
O 4
O 3
02
1

The coefficient of the Ammonia gas is 2

Explanation:

N2 + H2 ==>  NH3

Put a 2 in front of the NH3 to get the Ammonia balanced with the right number of nitrogens.

N2 + H2 ==>  2NH3

Now the problems is the hydrogens. There are 2 on the left and 2*3=6 on the right. The number of hydrogens is the number in the molecule * the balance or 3 * 2 = 6

But you have 2 in the hydrogen molecule. So you need 3 more molecules.

N2 + 3H2  ==>  2NH3

if you're asking what comes out, it's steam.

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).