The equation for the formation of water from hydrogen gas and oxygen gas is 2H2+O2→2H2O. How many grams of water can be made from 160 g of oxygen gas?

160 g

180 g

320 g

405 g

180g

Explanation:

H:1   O:16

2H2+O2 → 2H2O

 2   2(16)       2(1)+(16)

        32              18

Now,

       32g of O → 2(18)g of H2O

       160g of O → 2(18)g divides by 32g times 160g

                            =180g

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

c. is the answer

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