Write a balanced chemical ewuation for copper (II) sulphate reacting with iron (iii) hydroxide

When balancing chemical equations our goal is to have the same number of each type of atom on both sides of the equation.

Only change the coefficients (these are the numbers in front substances).

Coefficients are the numbers in front of the molecule.

Never change the subscripts (the small numbers after elements).

Coefficients are the numbers in front of the molecule.

How to Balance:

CuSO4 + NaOH → Cu(OH)2 + Na2SO4

Word equation: Copper (II) Sulfate plus Sodium Hydroxide → Copper (II) hydroxide + Sodium sulfate

Type of Chemical Reaction: For this reaction we have a double replacement reaction.

Balancing Strategies: To balance this reaction be sure to count all of the oxygen atoms on both sides of the equation.

Note that the 2 in Cu(OH)2 applies to all of the atoms in the parentheses.

Balanced Equation: CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4

58750.08068 is the answer i think

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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