Calculate the wavelength (in nm) of a photon emitted when an electron transitions from n = 3 to n = 2 in a hydrogen atom.
O 730 nm
O 657 nm
O 846 nm
O 308 nm
O 591 nm

Answer

657nm

Explanation

wavelength= 1/wavenumber

but wavenumber = RH×Z^2( (1/n1^2)-(1/n2^2))

where RH is the Rydberg constant = 1.0976×10^7

Z is the atomic number

n1 & n2 are orbitals

=(1.0976×10^7)×(1^2)×(1/4-1/9)

=1524444.444

but wavelength= 1/wavenumber

Therefore wavelength = 1/1524444.444

= 6.5597× 10^-7m

≈ 657nm

yes

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