if we approximate the atmosphere to be 79% nitrogen (n2) and 21% oxygen (o2) by volume, calculate the density of air (kg/m3) at stp conditions (0oc, 1 atm). hint: 1 mole of gas occupies 22.414 l at stp.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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