28.5g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark, from this information, calculate the density of iron.

Explanation:

this is a very easy question, you just need to know the formula of density, the mass and volume.

you're given the mass of the iron which is 28.5g and when it is submerged into a cylinder containing 45.50 ml, it rises to 49.10 ml. the volume of water displaced gives you the volume of the iron. thus,

V² - V¹ = 49.10 ml - 45.50 ml

V of iron = 3.6 ml

now that you know both the mass and volume, you can work out the question.

density (ρ) = mass / volume

ρ = m/v

ρ = 28.5 g / 3.6 ml

ρ = 7.916666...

ρ = 7.92 g/ml (3 sf)

hope this helps you!

- s.

1 is the answer to this problem

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.