The graph gives information on greenhouse gas emissions from industries. Which questions would help clarify the evidence from this graph

The correct answers are A) what caused a drop in GHG emissions in 2009? And E) which type of industries were included in the study?

The graph gives information about Green House Gase emissions from industries. The questions that would help clarify the evidence from this graph are what caused a drop in GHG emissions in 2009? and which type of industries were included in the study?

If we want to clarify the evidence of the data showed in the graph, we need to ask two questions: what caused a drop in GHG emissions in 2009?, and which type of industries were included in the study?

This way we could understand what happened in 2009 that made the emissions dropped so drasctically and notoriously, in order to take this into consideration for the future. And the other interesting question should be the kind of industries that were researched. This way we can know what kind of industries are the ones that emit the most GHG emissions, or if we are not taking in consideration other important pollutant industries that should be included in the study to make it more accurate.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g