determine the concentration of a solution made by dissolving 10.0 G of sodium chloride in 0.7 5L of solution

Concentration is measured through multiple equations including mole fraction, % mass, ppm (parts per million), ppb (parts per billion), molarity, and molality.

Based on the information you provided, your answer is either by mole fraction or molarity.

mole fraction:

moles a/ total moles (never greater than 1 and has no unit)

10.0g NaCl • 1 mol
——— = 0.1711156742 mol
58.44 g (molar mass of NaCl)

0.75 L solution • 1 mol
——— = 0.0334821429 mol
22.4 L (stp constant)

.1711156742 mol NaCl + 0.0334821429 mol solution = 0.2045978171 total mol

.1711156742 mol NaCl / 0.2045978171 total mol = 0.8363514168 or 0.84

0.84

molarity:

mol solute/L solution (unit- M)

10.0g NaCl • 1 mol
——— = 0.1711156742 mol
58.44 g (molar mass of NaCl)

0.1711156742 mol NaCl / 0.75 L solution = 0.2281542323 M or 0.23 M

0.23 M

hope this helps :)

What do you mean by that? like the contents? the thc level?

(no3)⁻n has oxidation number x,o has oxidation number -2.(x*1 -2*3) charge of the nitrate ion, and we know that charge of the nitrate ion =-1.so,(x*1 -2*3) =-1x-6=-1x=+5answer a. +5.