How many liters of a 2.50 M KNO3 solution can be prepared from 60.0 g of KNO3?

0.2374 L

Explanation:

Formula for number of moles is;

Number of moles = mass/molar mass

molar mass of KNO3 = 101.1 g/mol

Thus;

n = 60/101.1

n = 0.5935

Formula for molarity is;

M = n/V

2.5 = 0.5935/V

V = 0.5935/2.5

V = 0.2374 L

the volume increases

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