Chemistry, 02.04.2022 23:40 9444

Is Fossil Fuel OverUse threatening your health by: Erin Cobb
Summary Paragraph (last sentence MUST conclude) Your first sentence must include the title/author of the article, verb, and central idea

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Answer from: kkruvc

Answer/Explanation:

Is Fossil Fuel Overuse threatening your health? Pollution that not only can harm health but also foster climate changes. The Overuse of fossil fuel damages our health. For Instance, Burning fossil Fuel increates a carbon dioxide; to much CO_2 is harmful to our health. This Proves that Fossil fuel can harm our health. Burning fossil fuels could lead to developmental delays in children. This tells us it can be very harmful for children. To much Co_2 can cause children to have adhd. In the text it states children exposed to air pollution from fossil fuels have a significantly greater chance of developmental.Fossil fuels burning cause global warning that makes it difficult to grow crops. This reveals that Fossil fuels can be harmful for the environment. Burning fossil fuels can cause extreme weather and it can cause people to lose their homes and lives.

~Lenvy~

Answer from: raiindrxp

Ofc fossil fuel overuse threaten my health.

Explanation:

Is Fossil Fuel OverUse threatening your healthIs Fossil Fuel OverUse threatening your healthIs Fossil Fuel OverUse threatening your healthIs Fossil Fuel OverUse threatening your healthIs Fossil Fuel OverUse threatening your healthIs Fossil Fuel OverUse threatening your healthIs Fossil Fuel OverUse threatening your healthIs Fossil Fuel OverUse threatening your health. YES.

Answer from: Quest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

$\delta h_{reaction}\times \text{moles of no}=-311.85kj/mol\times 0.49 mol=-152.80kj/mol$

Answer from: Quest

257 grams h2o i think

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Is Fossil Fuel OverUse threatening your health by: Erin Cobb
Summary Paragraph (last sentenc...