Butane (c4h10) is the liquid fuel in lighters. how many grams of carbon are present within a lighter containing 7.25 ml of butane? (the density of liquid butane is 0.601 g/ml.) express the mass in grams to three significant figures.

Density is calculated using the following rule:
density = mass / volume

We have the volume of butane = 7.25 ml and the density of butane = 0.601 g/ml
mass of butane = volume x density = 7.25 x 0.601 = 4.35725 grams

From the periodic table:
mass of carbon = 12 grams and mass of hydrogen = 1 gram
mass of C4H10 = 4(12) + 10(1) = 58 grams
Therefore, each 58 grams of butane contains 48 grams of carbon.
To know the mass of carbon in 4.35725 grams of butane, we will simply do cross multiplication as follows:
mass of carbon = (4.35725 x 48) / 58 = 3.606 grams