Rom the equation for the decomposition of nahco3, what is the weight in grams lost when 1.000 g of nahco3 is decomposed thermally

1) Chemical reaction (thermal decomposition)

2NaHCO3 (s) ---> Na2CO3 (s) + H2O (g) + CO2(g)

2) Reasoning

The lost of mass is due to the lost of the gases H2O and CO2.

So, you can calculate the mass of Na2CO3 obtained from 1.000 g NaHCO3, and the difference will be the mass lost.

2) Convert 1.000 g of NaHCO3 to number of moles

molar mass NaHCO3: 1*23g/mol + 1*1g/mol + 1*12g/mol + 3*16g/mol = 84 g/mol

number of moles = mass in grams / molar mass = 1.000 g / 84 g/mol = 0.01190 moles

3) Use therotecial molar ratios:

2 moles NaHCO3 : 1 mol Na2CO3

=> 0.01190 mol NaHCO3 / x = 2 mol NaHCO3 / 1mol Na2CO3

=> x = 1mol Na2CO3 * 0.01190 mol NaHCO3 / 2 mol NaHCO3

=> x = 0.00595 mol Na2CO3

4) Convert 0.0595 mol Na2CO3 to mass

molar mass Na2CO3: 2*23g/mol + 1*12g/mol + 3*16g/mol = 106 g/mol

mass in grams = number of moles * molar mass = 0.00595 mol * 106 g/mol = 0.6307 g

5) lost mass

1.000g - 0.6307g = 0.3693 g

0.3693 g

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