How many grams of li3n can be formed from 1.75 moles of li? assume an excess of nitrogen. 6 li(s) + n2(g) â 2 li3n(s) how many grams of li3n can be formed from 1.75 moles of li? assume an excess of nitrogen. 6 li(s) + n2(g) â 2 li3n(s) 18.3 g li3n 61.0 g li3n 58.3 g li3n 20.3 g li3n 15.1 g li3n?

20.3 g First, determine how many moles of Li3N you can produce from 1.75 moles of Li. Since each molecule of Li3N requires 3 atoms of Li, that means that from 1.75 moles of Li, you can only produce 1.75 / 3 = 0.5833 moles of Li3N. Now compute the molar mass of Li3N Atomic weight of Lithium = 6.941 Atomic weight of Nitrogen = 14.0067 Molar mass of Li3N = 3 * 6.941 + 14.0067 = 34.8297 g/mol Now multiply the molar mass by the number of moles 34.8297 * 0.5833 = 20.316 g Of the available 5 choices, only 20.3 g is correct.

Yes i think so not 100 percent sure though

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