What celsius temperature, t2, is required to change the volume of the gas sample in part a (t1 = 43 ∘c , v1= 1.13×103 l ) to a volume of 2.26×103 l ? assume no change in pressure or the amount of gas in the balloon?

In this case, you are given the temperature and volume of the gas. To answer this question, you will need to use PV=nRT formula. Since the number of molecule and pressure is not changed then you can put 1 in both equations. The formula will become:

PV=nRT 
1 V= 1 T
V=T
T/V= 1

Dont forget that the celcius unit should be converted into kelvin. Then the calculation to find the temperature would be: 
T1/V1 = T2/V2
(43+273)/ 1.13x10^3 = T2/ 2.26 x 10^3
T2= (2.26 * 10^3) / (1.13 * 10^3) * (43+273)
T2= 2* 316= 632° K= 359°C

D. h2o + h2o > h3o + oh- confirmed.

The answer to this question is a