Write the balanced molecular and net ionic equations for the reaction between aluminum metal and silver nitrate. identify the oxidation and reduction half-reactions.

Well in this case, silver nitrate is reduced:

Ag+  +  e−  → Ag(s) ↓

Meanwhile, the aluminum is oxidized forming a positive ion:

Al(s)  →  Al3+  +  3e−

To get the overall reaction,  we add the half equations so that the electrons are eliminated:

Al(s)  +   3Ag+  →  Al3+  +  3Ag(s)

And similarly:

Al(s)  +  3AgNO3(aq)  →  Al(NO3)3(aq)  +  3Ag(s)

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2