Calculate the enthalpy change for the thermite reaction: 2al(s)+fe2o3(s)→2fe(s)+al2o3(s), δh∘rxn=−850 kj when 8.00 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3. express your answer to three significant figures and include the appropriate units.

Enthalpy change for the balanced equation is -850kj
And from the balanced equation we come to know that for 2 moles of Al, the value is -850kj
for 1 mole of Al = -850/2 = -425 kj
We have to find the enthalpy change for 8 moles of Al = 8 x -425 = 3400kj
Thus, the enthalpy change for 8 mol of Al is -3400kj.

The answer is bhope this

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