Asap, will give brainiest 1. based on the data in figure 1. is mixture c a homogeneous or heterogeneous mixture? explain your answer. 2. which of the mixtures in figure 1 is a solution? explain how you know

Answer 1. mixture C is a heterogeneous solution.

This is because heterogeneous solution :

scatters light- solute particles are large in size as they are partially or fully insoluble in solvent  and can be seen with naked eyes, so whenever light is passed through it ,path of light is visible.separates into two  different layers-presence of physical boundaries in between the  layers of solute and of the solvent.can be separated out by filtration- due to formation of two different layers both the layers can be separated easily with the help of filtration technique.  

Answer 2. mixture B is a solution.

Solutions are homogeneous solution and homogeneous solution:

doesn't scatter light- due to very small size of solute particles are not visible to naked eyes, so whenever light is passed its path is not visible.doesn't separate out into layers-  solute particles are completely soluble in solvent so they do not form any layers.cant be separated out by filtration - miscibility makes it impossible to filter out the solute particles from the solvent.

Sorry i dont understand the question can you rephase it?

Electron equations of the given changes are as follow,a)                              cu      →      cu⁺²  + 2e⁻b)                              mg⁺²  +  2 e⁻      →      mgc)                              cl⁻    →      cl  +  1e⁻d)                              s  +  2 e⁻    →      s²⁻e)                                o²⁻      →      o  +  2 e⁻f)                              p  +  3 e⁻    →      p³⁻g)                              fe²⁺    →      fe³⁺  + 1 e⁻h)                              s²⁻    →      s⁴⁺  +  6 e⁻