Ajar containing only nickels and dimes contains a total of 60 coins. the value of all the coins in the jar is $4.45. solve by elimination to find the amount of nickels and dimes that are in the jar.

1 nickle = 5 cents

1 dime = 10 cents

$4.45 = 445 cents

let

n = the number of nickles, n>=0

d = the number of dimes, d>=0

a jar containing only nickels and dimes contain a total of 60 coins:

n + d = 60

the value of all the coins in the jar is $4.45:

5n + 10d = 445

by solving the system of equations:

n + d = 60

5n + 10d = 445

we find:

n = 31 nickels

d = 29 dimes