How many moles of glycerin (c3h5(oh)3) are consumed in this reaction? 14kmno4 + 4c3h5(oh)3 es001-1.jpg 7k2co3 + 7mn2o3 + 5co2 + 16h2o

Ans: 0.709 moles glycerin

The given reaction is:

14KMnO4 + 4C3H5(OH)3 → 7K2CO3 + 7Mn2O3 + 5CO2 + 16H2O

a) Based on the reaction stoichiometry:

5 moles of CO2 requires 14 moles of KMnO4

Therefore, 0.886 moles of CO2 would correspond to:

= 0.886 moles CO2 * 14 moles KMnO4/5 moles CO2

= 2.48 moles

b) Again from the reaction stoichiometry:

5 moles of CO2 requires 4 moles of glycerin

therefore, 0.886 moles of CO2 would consume:

= 0.886 moles CO2 * 4 moles glycerin/5 moles CO2

= 0.709 moles

2.48  0.709

i got it right on edg so enjoy

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.