Calculate the molarity of a solution that contains 15.7g of caco3 dissolved in enough water to make 275 ml of solution

0.570 M (note the capital M, this is molarity. Using m denotes molality. Molarity is represented by moles of solute over the liters of solution. In this problem we are given the mass of the solute and volume of solution. The calculations is follows: (15.7 g CaCO3/275 mL of solution) x (1 mole CaCO3/ 100.0869 g of CaCO3) x (1000 mL of solution/ 1 L of solution) = 0.570 M CaCo3.