What maximum amount of ammonia in kilograms can be synthesized from 5.22 kg of h2 and 31.5 kg of n2? express your answer in kilograms to one decimal place?

Equation: N2(g) + 3H2(g) → 2NH3(g) Check for limiting reactant Molar mass N2 = 28g/mol mol N2 in 31,500g = 31,500/28 = 1,125 mol N2 This will require 1,125*3 = 3,375 mol H2 Molar mass H2 = 2g/mol Mol H2 in 5,220g = 5,220/2 = 2,610 mol H2 The H2 is limiting From the equation: 3 mol H2 will produce 2mol NH3 2610 mol H2 will produce 2610*2/3 = 1,740 mol NH3 Molar mass NH3 = 17g/mol Mass of 1740 mol NH3 = 1740*17 = 29,580g NH3 produced Mass of NH3 produced = 29.6kg

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