Abasketball is bounced from a height of 1.13 m above the ground. during its descent, it converts potential energy to kinetic energy. assuming it started its descent from rest, what is its final velocity (in m/s) upon impact with the ground?

The final velocity is 4.71 m/s

Explanation:

The potential energy corresponding to a body of mass (m) at a height (h) is given as:

where g = acceleration due to gravity = 9.8 m/s2

The kinetic energy of a body of mass (m) moving at a velocity (v) is:

It is given that:

the height (h) from which the basketball hits the ground = 1.13 m

Based on equation (1), the PE is:

During its descent, all the potential energy gets converted to kinetic energy

4d^55s^1 ( third choice)