What would be the major product if 1,4-dibromo-4-methylpentane was allowed to react with one equivalent of silver nitrate in ethanol?

a) Iodide is a strong nucleophile but a weak base, so SN2 is the preferred reaction. Only the bromine on C1 is eligible to undergo SN2, so that one will be replaced by iodide. b) Silver ion tends to suck off a halide ion and leave a carbocation, which means E1 and SN1. If there's only one equiv, then the tertiary bromide on C4 is the one that will go. The resulting carbocation can give: E1 products 5-Br-2-Me-2-pentene (major, trisub) and 5-Br-2-Me-1-pentene (disub, minor). SN1 product 5-bromo-2-ethoxy-2-methylpentane

The independent variable is the type of music.the dependent variable is the pulse rate.the intervening variable is the age of the subject.if the mother does not like rock, her pulse is likely to not increase.the same might be true for the sister.the friend may like rap and gets excited.to establish cause/effect relationship, all of the subjects must be consistent.hope i .

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na