What is the concentration of nacl in a solution if titration of 15.00 ml of the solution with 0.2503 m agno3 requires 20.22 ml of the agno3 solution to reach the end point? agno3(aq) + nacl(aq) ⟶ agcl(s) + nano3(aq)?

We see from the balanced equation that there is only 1 mole to 1 mole ratio.

Calculate moles of AgNO3:

moles AgNO3 = 0.2503 M * 0.02022 L = 0.00506 mol

This is equal to moles of NaCl,

moles NaCl = 0.00506 mol

So the concentration is:

Concentration = 0.00506 mol / 0.015 L = 0.3374 M

the answer is d.) potassium