Calculate the ph of a saturated solution of strychnine (16 mg/100ml).

The Initial concentration of strychnine which has a chemical formula of C21H22N2O2, can be found from the mass of the strychnine, the molar mass, and the volume of the solution.

[C21H22N2O2 ] initial = (mass of strychnine / molar mass of strychnine) / volume of solution

                                    = (0.016 g / 334.418 g/mol) / (0.100 L)

                                    = (4.78 x 10-5 mol) / (0.100 L)

                                    = 4.8 x 10-4 mol/L

[C21H22N2O2 ] initial = 9.46

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

the product of the pressure and volume is also constant