Draw the structure of bromous acid, hbro2. optimize formal charges.

It would be created like this

":" means lone pair of electrons, ignore the "~" 

H---O---Br===O: 

The formal charge would be as follows: 

H: 1-1/2(2)-0=0

O: 6-1/2(4)-4=0

Br: 7-1/2(6)-4=0 O: 6-1/2(4)-4=0 

Br can hold extra electrons because it can leak those electrons over to the D orbital.

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