What is the enthalpy change when 49.4 ml of 0.430 m sulfuric acid reacts with 23.3 ml of 0.309 m potassium hydroxide?

Potassium hydroxide commonly known as caustic potash is an inorganic compound with a chemical formula KOH which is a strong base that is marketed in several forms. 

H2SO4(aq) + 2KOH(aq) ---> K2SO4(aq) + 2H2O(l) H°= –111.6 kJ/mol

The answer in this question is -0.402 kJ

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.