Asample of a hydrocarbon contains 20.75 g c and 4.25 g h. its molar mass is 58.04 g/mol. what is its empirical formula c2h5 ch2 ch c5h

Answer : The empirical formula is,

Solution : Given,

Mass of C = 20.75 g

Mass of H = 4.25 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

The ratio of C : H = 1 : 2.5

In the whole number the ratio of C : H = 2 : 5

The mole ratio of the element is represented by subscripts in empirical formula.

Therefore, the empirical formula is,

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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