Which of the following does not show the law of conservation of mass? \ a. 24 g of mg burn in 32 g o2 to produce 56 g of mgo. b. 18 g of mg burn in 24 g o2 to produce 24 g of mgo. c. 2 atoms of mg react with 1 molecule of o2 to produce 2 units of mgo. d. 1 atom of mg reacts with 1 atom of o to produce a unit of mgo that contains 2 atoms.

Option (B) is the correct answer.

Explanation:

According to law of conservation of mass, mass can neither be created nor it can be destroyed. It can only be transformed from one form to another.

So, it means mass of reactants must be equal to the mass of products in order to follow law of conservation of mass by a chemical reaction.

(a)    When 24 g of Mg burn in 32 g to produce 56 g of MgO. So, mass of reactants is (24 g + 32 g) = 56 g. Mass of products is 56 g. Hence, it is following law of conservation of mass.

(b)    18 g of Mg burn in 24 g  to produce 24 g of MgO. So, mass of reactants is (18 g + 24 g) = 42 g. Mass of products is 24 g. Hence, it is not following law of conservation of mass.

(c)    2 atoms of Mg react with 1 molecule of to produce 2 units of MgO. So, mass of reactants is = 56 g. Mass of products is = 56 g. Hence, it is following law of conservation of mass.

(d)   1 atom of Mg reacts with 1 atom of O to produce a unit of MgO that contains 2 atoms. So, mass of reactants is = 28 g. Mass of products is (12 g + 16 g) = 28 g. Hence, it is following law of conservation of mass.

Thus, we can conclude that the equation which does not follow law of conservation of mass is that  18 g of Mg burn in 24 g to produce 24 g of MgO.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

c. 4.54 x 10–12 j happens to be correct