How many moles of potassium hydroxide (koh) are needed to completely neutralize 1.56 mol phosphoric acid (h3po4)?

Answer : The number of moles of potassium hydroxide (KOH) are needed to completely neutralize are 4.68 moles.

Explanation :

The balanced chemical reaction will be:

From the balanced chemical reaction we conclude that,

As, 1 mole of neutralizes 3 moles of KOH

So, 1.56 mole of neutralizes moles of KOH

Thus, the number of moles of potassium hydroxide (KOH) are needed to completely neutralize are 4.68 moles.

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