How many bromine atoms are present in 35.2 g of ch2br2?

2.44*10²³ Br atoms.

Explanation:

To solve this problem we need to calculate the number of moles of CH₂Br₂ in 35.2 g.

35.2 g / 173.8 g·mol⁻¹ = 0.2025 mol CH₂Br₂

Now we use Avogadro's number to calculate the number of Br atoms in 0.2025 moles of CH₂Br₂, keeping in mind that there are 2 Br atoms for each CH₂Br₂ molecule:

0.2025 mol CH₂Br₂  * 2.44*10²³ Br atoms

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?