The chemical equation below shows the formation of aluminum oxide (al2o3) from aluminum (al) and oxygen (o2). 4al + 3o2 mc029-1.jpg 2al2o3 the molar mass of o2 is 32.0 g/mol. what mass, in grams, of o2 must react to form 3.80 mol of al2o3?

the complete reaction for the formation of aluminum oxide is as follows;

4al + 3 > 2

so if the molar mass of the is 32.0 g/mol and

so, to form 3.80 mol of

(3.80 mol ) x (3 mol ) x (32.0 g )

dividing by 2 because two moles of will be formed;

∴ 364.8/2   = 182.4g