Chlorine gas reacts with fluorine gas to form chlorine trifluoride. cl2(g)+3f2(g)→2clf3(g) a 2.15 l reaction vessel, initially at 298 k, contains chlorine gas at a partial pressure of 337 mmhg and fluorine gas at a partial pressure of 746 mmhg . part a identify the limiting reactant and determine the theoretical yield of clf3 in grams.

The solution for the problem is:746 mmHg of F2 would respond wholly with 746 x (1/3) = 249 mmHg of Cl2, nonetheless there is more Cl2 current than that, so Cl2 is in excess and F2 is the limiting reactant. 
n = PV / RT = (746 mmHg F2) x (2.15 L) / ((62.36367 L mmHg/K mol) x (298 K)) = 0.0863 mol F2 
(0.0863 mol F2) x (2 mol ClF3 / 3 mol F2) x (92.4482 g ClF3/mol) = 5.3210 g ClF3