Consider the reaction zn + no− 3 → nh3 + zn(oh)2− 4 carried out in an aqueous basic solution. when the equation is properly balanced, what is the total charge on the product side of the equation?

Oxidation half-reaction: Zn  + 4 OH⁻ → Zn(OH)₄²⁻ + 2 e-  

Reduction half-reaction: NO₃⁻ + 6 H₂O + 8 e-→ NH₃ + 9 OH⁻

Adding both reaction, we get the overall complete balanced equation:

4Zn + NO₃⁻ + 6 H₂O + 7 OH⁻  → 4 Zn(OH)₄²⁻ + NH₃

Thus, the charge in the product side is 4*-2 = -8.

your answer is c) plasma

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