Bombarding plutonium-239 with an alpha particle creates an isotope of curium. balance the equation. 239 94 pu + 4 2 he → a b cm + c d n identify the values for the unknown letters. a is b is c is d is

Value of a is 242, Value of b is 96, Value of c is 1 and Value of d is 0.

Explanation:

It is given that an isotope of plutonium is bombarded with an alpha particle which is also known as a helium particle.

The equation for the bombarding of alpha particle to plutonium-239 follows:

The mass of neutron released is +1 unit and charge is 0.

As we know that every equation must be balanced and must follow law of conservation of mass.

Mass on the reactant side = Mass on the product side

Mass on reactant side = 239 + 4 = 243 units

Mass on the product side = Mass of curium + 1 = 243

So, mass of curium comes out to be 242.

And, atomic number of curium = 94 + 2

Thus, the balanced chemical equation follows:

Hence, value of a is 242, Value of b is 96, Value of c is 1 and Value of d is 0.

2b2t

explanation:

2b2t

im pretty sure its b