A50 l cylinder is filled with argon gas to a pressure of 10130.0 kpa at 300°c. how many moles of argon gas does the cylinder contain? (given: r = 8.314 l∙kpa/k∙mol) 2519.142 mol

To answer this question, we will use the general gas law which states that:
PV = nRT where:
P is the pressure of the gas = 10130.0 kPa
V is the volume of the gas = 50 liters
n is the number of moles that we want to calculate
R is the gas constant = 8.314 L∙kPa/K∙mol
T is the temperature = 300+273 = 573 degree kelvin

Substitute with the givens in the equation to get the number of moles as follows:
10130 * 50 = n * 8.314 * 573
506500 = 4763.922 n
n = 506500 / 4763.922
n = 106.3199 moles

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

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