Calculate the number of molecules of hydrogen that are required to completely react with 75.9l of oxygen at stp. the product of this reaction is water. show all work including balanced equation.

2H₂ + O₂ = 2H₂O
n(O₂)=V/Vm, V-volume, Vm=22,4 dm³/mol at standard condition.
n(O₂)=75,9 dm³/22,4dm³/mol=3,39 mol
n(O₂):n(H₂)=1:2, n(H₂)=6,78 mol
N=n·Na(Avogadro number), N(H₂)=6,78 mol·6·²³ 1/mol = 40,68·10²³ molecules

 = 40,68·10²³ molecules

Hope this helps!

Alpha particles have positive charge, beta particles have negative charge, and answer 4 just doesn’t make sense. thus, you are left with only one possible answer.

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