When aluminum oxidizes in air it forms aluminum oxide (al2o3) if a 51 sheet?

mol Al2O3 x 1 mol Al/ 2 mol Al2O3= .25 mol Al The balanced equation tells us that it takes 4 moles of Al to produce 2 moles of Al2O3. 0.50 moles Al2O3 x (4 moles Al / 2 moles Al2O3) = 1.0 moles Al 1.0 moles Al x (27.0 g Al / 1 mole Al) = 27.0 g Al

The answer is c. 320 g

The answers is a nuclear changes