Heat released when 25.0 grams of water freezes

To calculate the amount of heat entering or leaving a system, the equation Q=mcT is used. Where m = mass (in grams) c = specific heat capacity (J/g°C) ΔT = change in temperature (°C) Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C. The mass given is 25.0 grams. As for the change in temperature, I will assume that it start off at room temperature, 25°C. 25°Câ’0°C=25°C Q=25gramsâ‹…4.19J/g°Câ‹…25°C Q=2618.75J

Most likely a is the answer - because  you generate   38 atp's but also consume an atp.   each atp gives approx. less than 4 kcal so probably a is the closest answer.

Idon't know hope someone you