What is the percent by mass of water present in 1.0 mole of caso4 times 2h20?

We have that the the percent by mass of water present  is mathematically given as

x=20.9%

Question Parameters:

the percent by mass of water present in 1.0 mole of caso4 times 2h20

Generally the equation for the Molecular mass of Caso4  is mathematically given as

40.1 grams/mole + 32.1 grams/mole +16 x 4+ water 18.0 grams/mole x 2 = 172.2 grams/mole

Since, water's Mass number is 32

X=36.0/ 172.2

x= 0.209059

x=20.9%

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c. 4.54 x 10–12 j happens to be correct