Chemistry, 04.08.2019 13:30 xxtonixwilsonxx

Identify the kinds of intermolecular forces that are present in each element or compound. h2s

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Answer from: craincrew5239

Dipole-dipole

Explanation:

H and S are nonmetals, so they form covalent bonds.

The molecule has a central atom S, 2 ligands H, and 2 lone pairs of electrons around the central atom. According to the VESPR theory, the molecular geometry is bent.

The bonds are slightly polar because the difference in electronegativity is EN(S) - EN(H) = 2.5 - 2.1 = 0.4. However, due to the bent geometry, the individual dipole moments are added, resulting in a net dipole moment.

Since H₂S molecules are polar, the intermolecular forces between H₂S molecules are dipole-dipole.

Answer from: Quest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.

Answer from: Quest

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Identify the kinds of intermolecular forces that are present in each element or compound. h2s...

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