Chemistry, 04.08.2019 05:00 mrsjenrucker
What is the molarity (m) of a solution prepared by dissolving 15.0 grams of na3po4 in enough water to make 250.0 ml of solution?
Answers: 1
(solute) = 15 g![Molarity=\frac{\text{Moles of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}[tex]Now put all the given values in this formula, we get the molarity of the solution.[tex]Molarity=\frac{15g\times 1000}{163.94g/mole\times 250ml}=0.365mole/L](/tpl/images/0168/2467/caeda.png)
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What is the molarity (m) of a solution prepared by dissolving 15.0 grams of na3po4 in enough water t...
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