Consider the reaction 2so2(g) + o2(g) mc021-1.jpg 2so3(g). substance mc021-2.jpghf (kj/mol) s (j/(molmc021-3.jpgk)) so3(g) –396 130.58 so2(g) –297 191.50 o2(g) 0 205.00 what is the mc021-4.jpggrxn of this reaction, and would it be spontaneous or nonspontaneous at 300.0 k? use mc021-5.jpgg = mc021-6.jpgh – tmc021-7.jpgs. –296 kj/mol, spontaneous –296 kj/mol, nonspontaneous –100 kj/mol, spontaneous –100 kj/mol, nonspontaneous

altitude, density, pressure

air gets less dense the higher the altitude and also the air pressure is less as altitude rises.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :