Mno2 + 4 hcl → cl2 + mncl2 + 2 h2o given 145.7 grams of mno2, how much hydrochloric acid (hcl) is needed to use up the mno2 completely (mm in g/mol: mno2=86.94, hcl= 36.46, cl2=70.9, mncl2=125.84, h2o=18.02)? 244.4 g 10.55 g 145.5 g 1407 g

Count the number of each type of atom in the equation below, and then balance the equation. write in the numbers of atoms and coefficients. add a 1 if there should be no coefficient. cs2(l) + o2(g) → co2(g) + so2(g) c [ ] s [ ] o > c [ ] s [ ] o [ ] cs2(l) + [ ] o2(g) > [ ] co2(g) + [ ] so2(g)