Suppose you seal 30 g of ag2o(s) in a 1.00 liter evacuated vessel, and heat it to 450 k. what pressure (of o2) would develop in the vessel at equilibrium?

We would use the ideal gas equation. PV = NRT
 No of moles of ag2o = 30/ 231.735 = 0.12944
 The chemical reaction is given by
  2 Ag2O = 4 Ag + O2
  2* 0.12944 of Ag2O requires 0.12944 of O2
 So we have P * 1 = 0.258 * 8.2 * 450
  P = 952.02 atm

The second and last option are the answers